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Proof of Derivative of ln(x)

The proof of the derivative of natural logarithm ln(x) is presented using the definition of the derivative. The derivative of a composite function of the form ln(u(x)) is also included and several examples with their solutions are presented.

Proof of the Derivative of ln(x) Using the Definition of the Derivative

The definition of the derivative f of a function f is given by the limit f(x)=limh0f(x+h)f(x)h Let f(x)=ln(x) and write the derivative of ln(x) as
f(x)=limh0ln(x+h)ln(x)h
Use the formula ln(a)ln(b)=ln(ab) to rewrite the derivative of ln(x) as
f(x)=limh0ln(x+hx)h=limh01hln(x+hx)
Use power rule of logarithms ( alny=lnya ) to rewrite the above limit as
f(x)=limh0ln(x+hx)1h=limh0ln(1+hx)1h
Let y=hx
and note that
limh0y=0
We now express h in terms of y
h=yx
With the above substitution, we can write
limh0ln(1+hx)1h=limy0ln(1+y)1yx
Use power rule of logarithms ( lnya=alny ) to rewrite the above limit as
=limy01xln(1+y)1y
One of the definitions of the Euler Constant e is
e=limm0(1+m)1m
Hence the limit we are looking for is given by
limh0ln(1+hx)1h=limy01xln(1+y)1y=1xlne=1x
Conclusion: ddxln(x)=1x



Derivative of the Composite Function y=ln(u(x))

We now consider the composite natural logarithm of another function u(x). Use the chain rule of differentiation to write
ddxln(u(x))=dduln(u(x))ddxu
Simplify
=1uddxu
Conclusion

ddxln(u(x))=1uddxu

Example 1
Find the derivative of the composite natural exponential functions

  1. f(x)=ln(x2x2)
  2. g(x)=ln(x3+1)
  3. h(x)=ln(x2+2x5)

Solution to Example 1


  1. Let u(x)=(x2x2) and therefore ddxu=ddx(x2x2)=x24x(x2)2
    Apply the rule for the composite natural logarithm function found above
    ddxf(x)=1uddxu=1x2x2×x24x(x2)2

    =x2x2×x24x(x2)2=(x2)x(x4)x2(x2)2
    Cancel common factors from numerator and denominator
    =(x4)x(x2)


  2. Let u(x)=x3+1 and therefore ddxu=ddxx3+1=3x22x3+1.
    Apply the above rule of differentiation for the composite natural logarithm function
    ddxg(x)=1uddxu=1x3+1×3x22x3+1
    =3x22(x3+1)


  3. Let u(x)=x2+2x5 and therefore ddxu=2x+2
    Apply the rule of differentiation for the composite exponential function obtained above
    ddxh(x)=1uddxu=1x2+2x5×(2x+2)
    =2x+2x2+2x5


More References and links

derivative
definition of the derivative
Chain Rule of Differentiation in Calculus.