How to find the zeros of functions; tutorial with examples and detailed solutions. The zeros of a function f are found by solving the equation f(x) = 0.
Example 1Find the zero of the linear function f is given by
Solution to Example 1To find the zeros of function f, solve the equation f(x) = -2x + 4 = 0 Hence the zero of f is give by x = 2
Example 2Find the zeros of the quadratic function f is given by
Solution to Example 2Solve f(x) = 0 f(x) = -2 x 2 - 5 x + 7 = 0 Factor the expression -2 x 2 - 6 x + 8 (-2x - 7)(x - 1) = 0 and solve for x x = -7 / 2 and x = 1 The graph of function f is shown below. The zeros of a function are the x coordinates of the x intercepts of the graph of f. ![]()
Example 3Find the zeros of the sine function f is given by
Solution to Example 3Solve f(x) = 0 sin (x) - 1 / 2 = 0 Rewrite as follows sin (x) = 1 / 2 The above equation is a trigonometric equation and has an infinite number of solutions given by x = ? / 6 + 2 k ? and x = 5 ? / 6 + 2 k ? where k is any integer taking the values 0 , 1, -1, 2, -2 ... The graph of f is shown below. The number of zeros of function f defined by f(x) = sin(x) - 1 / 2 are is infinite simply because function f is periodic. ![]()
Example 4Find the zeros of the logarithmic function f is given by
Solution to Example 4Solve f(x) = 0 ln (x - 3) - 2 = 0 Rewrite as follows ln (x - 3) = 2 Rewrite the above equation changing it from logarithmic to exponential form x - 3 = e 2 and solve to find one zero x = 3 + e 2
Example 5Find the zeros of the exponential function f is given by
Solution to Example 5Solve f(x) = 0 ex2 - 2 - 3 = 0 Rewrite the above equation as follows ex2 - 2 = 3 Rewrite the above equation changing it from exponential to logarithmic form x2 - 2 = ln (3) Solve the above equation to find two zeros of f x1 = square root [ln (3) + 2] and x2 = - square root [ln (3) + 2]
More References and linksApplications, Graphs, Domain and Range of Functions
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