Complex Numbers - Basic Operations







Definition of Complex Numbers

A complex number z is a number of the form

z = a + b i


where a and b are real numbers and i is the imaginary unit defined by

imaginary unit : i = sqrt(-1)


a is called the real part of z and b is the imaginary part of z.

Note that the set R of all real numbers is a subset of the complex number C since any real number may be considered as having the imaginary part equal to zero..

Complex Conjugate

The conjugate of a complex number a + b i is a complex number equal to

a - b i

Examples: Find the conjugate of the following complex numbers.

a) 2 - i , b) -3 + 4i , c) 5 , d) -5i

Solution to above example

a) 2 + i , b) -3 - 4i , c) 5 , d) 5i

Use calculator below to generate complex conjugate of any complex number.

Applet to generate complex conjugate : enter your complex number and press enter

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Addition of Complex Numbers

Addition of two complex numbers a + b i and c + d i is defined as follows.

(a + b i) + (c + d i) = (a + c) + (b + d) i

This is similar to grouping like terms: real parts are added to real parts and imaginary parts are added to imaginary parts.

Example: Express in the form of a complex number a + b i.

  • (2 + 3i) + (-4 + 5i)
  • (3i) + (-5 + 6i)
  • (2) + (-2 + 9i)


Solution to above example.

  • (2 + 3i) + (-4 + 5i) = (2 - 4) + (3 + 5) i = - 2 + 8 i
  • (3i) + (-5 + 6i) = (0 - 5) + (3 + 6) i = -5 + 9 i
  • (2) + (-2 + 9i) = (2 - 2) + (9) i = 9i
Addition can be done by grouping like terms.

(2 + 3i) + (-4 + 5i) = 2 + 3 i - 4 + 5 i = -2 + 8 i

Applet that Adds two complex numbers: enter your complex numbers and press enter

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Subtraction of Complex Numbers

The subtraction of two complex numbers a + b i and c + d i is defined as follows.

(a + b i) - (c + d i) = (a - b) + (b - d) i

Example: Express in the form of a complex number a + b i.

  • (2 - 5i) - (-4 - 5i)
  • (-7i) - (-5 - 6i)
  • (2) - (2 + 6i)


Solution to above example

  • (2 - 5i) - (-4 - 5i) = (2 - (-4)) + (-5 - (-5)) i = 6
  • (-7i) - (-5 - 6i) = (0 - (-5)) + (-7 - (-6)) i = 5 - i
  • (2) - (2 + 6i) = (2 - 2) - 6 i = -6 i

    Note: subtraction can be done as follows:

    (a + b i) - (c + d i) = (a + bi) + (- c - d i) and then group like terms

    Exapmple:

    (2 - 5i) - (-4 - 5i) = 2 - 5 i + 4 + 5 i = 6

Applet that subtract two complex numbers: enter your complex numbers and press enter

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Mulyiply Complex Numbers

The multiplication of two complex numbers a + b i and c + d i is defined as follows.

(a + b i)(c + d i) = (a c - b d) + (a d + bc) i

However you do not need to memorize the above definition as the multiplication can be carried out using properties similar to those of the real numbers and the added property i 2 = -1. (see the example below)

Example: Express in the form of a complex number a + b i.

(3 + 2 i)(3 - 3i)
Solution to above example

(3 + 2 i)(3 - 3i)

Using the distributive law, (3 + 2 i)(3 - 3 i) can be written as

(3 + 2 i)(3 - 3 i) = (3 + 2 i)(3) + (3 + 2 i)(-3 i) = 9 + 6 i - 9 i -6 i 2

Group like terms and use i 2 = -1 to simplify (3 + 2 i)(3 - 3 i)

(3 + 2 i)(3 - 3 i) = 15 - 3 i

Applet that multiplies two complex numbers: enter your complex numbers and press enter

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Divide two Complex Numbers

We use the multiplication property of complex number and its conjugate to divide two complex numbers.

Example: Express in the form of a complex number a + b i.

  • (8 + 4 i) / (1 - i)

We first multiply the numerator and denominator by the complex conjugate of the denominator

[ (8 + 4 i)(1 + i) ]

Multiply and group like terms

[ (8 + 4 i)(1 + i) ] / [ (1 - i)(1 + i) ] =

[ 8 + 4 i + 8 i + 4 i 2 ] / [ 1 - i + i - i 2 ]

= (4 + 12 i ) / (2)

= 2 + 6 i

Applet that divides two complex numbers: enter your complex numbers and press enter

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Exercises

  • Find the complex conjugate of the following complex numbers

    a) 2 + 6 i

    b) -8 i

    c) 12

  • Write the following expressions in the form a + b i

    a) (2 - 8 i) + (-6 i)

    b) -8 i + (3 - 9 i)

    c) 6 - (3 - i)

    d) (2 - 3 i)(7 - i)

    e) (2 + 2 i) / (2 - 2i)

Solutions to above exercises

  • Find the complex conjugate.

    a) 2 - 6 i

    b) 8 i

    c) 12

  • Write the following expressions in the form a + b i

    a) (2 - 8 i) + (-6 i) = 2 - 14 i

    b) -8 i + (3 - 9 i) = 3 - 17 i

    c) 6 - (3 - i) = 3 + i

    d) (2 - 3 i)(7 - i) = 11 - 23 i

    e) (2 + 2 i) / (2 - 2i) = i






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Updated: 2 April 2013

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