To find a possible equation of an exponential function from its graph, we generally consider the form:
\[ f(x) = a \cdot b^{x-c} + d \]
It is recommended to review the tutorial on graphs of exponential functions to understand the properties of these graphs before attempting to find the function from a graph.
Find the exponential function of the form \( y = b^x \) whose graph is shown below.
From the graph, for \( x = 1 \), we have \( y = 4 \). Substituting into the equation \( y = b^x \):
\[ b^1 = 4 \implies b = 4 \]
Hence, the function is:
\[ y = 4^x \]
Find the exponential function of the form \( y = b^{x-c} \) whose graph is shown below.
From the graph: \( x = 2 \), \( y = 1 \) and \( x = 3 \), \( y = 2 \). Substituting into \( y = b^{x-c} \):
\[ b^{2 - c} = 1 \quad \text{(equation 1)}, \quad b^{3 - c} = 2 \quad \text{(equation 2)} \]
Equation (1) gives \( b^{2-c} = b^0 \implies 2-c = 0 \implies c = 2 \). Substituting \( c = 2 \) into equation (2):
\[ b^{3-2} = 2 \implies b = 2 \]
Hence, the function is:
\[ y = 2^{x-2} \]
Find the exponential function of the form \( y = -b^x + d \) whose graph is shown below.
From the graph: \( x = 0 \), \( y = 0 \) and \( x = 1 \), \( y = -2 \). Substituting into \( y = -b^x + d \):
\[ -b^0 + d = 0 \implies -1 + d = 0 \implies d = 1 \]
\[ -b^1 + 1 = -2 \implies b = 3 \]
Hence, the function is:
\[ y = -3^x + 1 \]
Find the exponential function of the form \( y = a \cdot b^x + d \) with horizontal asymptote \( y = 1 \).
Horizontal asymptote: \( y = d \implies d = 1 \). From the graph: \( x = 0 \), \( y = 4 \):
\[ a \cdot b^0 + 1 = 4 \implies a = 3 \]
Point \( (1,7) \) on the graph gives:
\[ 3 \cdot b^1 + 1 = 7 \implies b = 2 \]
Hence, the function is:
\[ y = 3 \cdot 2^x + 1 \]
Find the exponential function of the form \( y = a \cdot e^{x-1} + d \) with horizontal asymptote \( y = -2 \).
Horizontal asymptote: \( d = -2 \). For \( x = 1 \), \( y = -4 \):
\[ a \cdot e^{1-1} - 2 = -4 \implies a \cdot 1 - 2 = -4 \implies a = -2 \]
Hence, the function is:
\[ y = -2 \cdot e^{x-1} - 2 \]
Find the exponential function of the form \( y = a \cdot b^{x-1} + d \) with horizontal asymptote \( y = -1 \).
Horizontal asymptote: \( d = -1 \). From the graph: \( (1,2) \) and \( (2,5) \):
\[ a \cdot b^{1-1} - 1 = 2 \implies a = 3 \]
\[ 3 \cdot b^{2-1} - 1 = 5 \implies b = 2 \]
Hence, the function is:
\[ y = 3 \cdot 2^{x-1} - 1 \]
Find the exponential function for each graph below. The broken line represents the asymptote.